main(int argc, char **argv)
{
printf("%s\n",argv[1]);
}
Shows that C printf works well!
printf(argv[1]);
don't.
and perls printf $ARGV[0];
./fmt.pl %.6x
will produce
000000
Clifford, Shawn A <shawn.a.cliffordat_private> wrote:
> A better comparison is:
>
> ------ test_printf.pl ------
> #!/usr/local/bin/perl
>
> printf("%s\n", $ARGV[0]);
> _____________________________
> ./test_printf.pl %x%x%x%x%x%x
>
> Will product this:
>
> %x%x%x%x%x%x
>
> Showing that Perl's printf formatting works well.
>
> -- Shawn
>
> Larry W. Cashdollar wrote:
> > perl's print function doesnt use tokens to format its output like
> > printf() in C. A little test of this:
> >
> > ------- test.pl -------
> > #!/usr/bin/perl
> >
> > $ARGC = @ARGV;
> >
> > print $ARGV[0];
> >
> > $ ./test.pl %x%x%x%x%x%x
> >
> > Will produce this:
> >
> > %x%x%x%x%x%x
--
http://www.rshell.org
rastaat_private
This archive was generated by hypermail 2b30 : Fri Apr 13 2001 - 12:58:10 PDT