I conjecture that the extra chars will be stored somewhere and removed later on. Therefore, the login will
be parsed "cleanly".
Question 1: Is it possible to bypass the parser process through characters not included in the
parser table ?
Question2: Is there a naive buffer, without bounderies checking, just awaiting for the login ?
[]'s
Woody
> I have several yahoo accounts that have special characters in them (-, @ and
> $). Yahoo supresses some characters like @ but does not supress dashes or
> dots. Spaces are replaced with +'s. I guess } is supressed; I know this
> from ymessenger, and since yahoo uses the same authentication scheme for all
> their services, I'm sure it applies to yahoo groups too.
>
> $0.02
>
> Alonso Caballero said:
> > Subject: login yahoogroups.
> >
> > Saludos:
> >
> > Well; when i sign in to my account in yahoogroups, i typed other
> > characters in the end of my yahoo ID, for example:
> >
> > My 'original' yahoo ID is: alabedsarc
> >
> > But i type... pay attention...
> >
> > alabedsarc{
>
>
This archive was generated by hypermail 2b30 : Sun Jun 30 2002 - 10:35:35 PDT