Aiee :)
Hello!
On Wed, Jul 17, 2002 at 08:46:58AM -0700, Jeremy Junginger wrote:
> void function(int a, int b, int c) {
> char buffer1[5];
> char buffer2[10];
>
> void main() {
> function(1,2,3);
> }
>
> in "word" (4 byte) increments. That makes sense; however, when I
> generate the assembly code with the exact same code, I see that it is
> subtracting 40 rather than the expected 20
> (bufger1(5bytes=2words=8bytes+10bytes=3words=12bytes). This part looks
This should be due to default stack boundary that gcc uses. Version 2.7.2.3
(quite old) seems to have default stack boundary set to 2; that means
that you have stuff on a 2^2=4 byte, i.e. dword boundary.
For example, gcc 2.95.2 seems to set this default to 3, IIRC.
To change this, just compile using -mpreferred-stack-boundary=2 so you'll
get the "usual" stuff on a dword (4 byte) boundary.
Hope this helps.
bye bye
-- gg sullivan
--
Lorenzo Cavallaro `Gigi Sullivan' <sullivanat_private>
Until I loved, life had no beauty;
I did not know I lived until I had loved. (Theodor Korner)
This archive was generated by hypermail 2b30 : Sat Jul 20 2002 - 08:46:23 PDT