('binary' encoding is not supported, stored as-is) In-Reply-To: <004e01c319fb$7ec41050$0100a8c0@grotedoos> >Not true: "++i" will increase i first and return the result of that >increased i where "i++" will return i and then increase it: >-- example.js -- >var i=1; >document.write(++i); // prints 2, i=2; >document.write(i++); // prints 2, i=3; >-- cut here -- > Yes, of course. Again, I'm talking about C here, simply because I don't know JS to this level of detail. But... document.write((i==++i) + ' ' + (i==++i) + '<BR>'); Seems like ambiguous code that might rely on unspecified behaviours. Postincrement and preincrement are gotchas in C. For example the following code: i = 2; printf ("%d", i++ * i++); Often does not print 6 as you might think, but rather prints 4. The reason is that the postincrement operator increments the values before the next sequence point, not necessarily the next _operation_. I was just pointing out that using expressions like i == ++i seems a bit suspect. I'm not certain, but I believe a C compiler is free to do both increments prior to the rest of the expression. It does seem like it should always be a tautology, though. Do you get the same results if you write the same code less ambiguously? Cheers, ~ol
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