>While much of a disk's behavior (interleave, etc) is operating system >specific, the outermost track is where sector 0 resides, and the innermost >track is where the disk ends. The reason for this is because there are more >sectors on the outer track, so reads will be faster at the outer track >(since hard drives are fixed-speed and not variable-speed like CDROMs). I don't believe this statement is correct. The number of sectors per track/cylinder is, I believe, a constant. Optimizing the interleave becomes a much more complicated problem if sectors/cylinder is variable. The interleave is basically an indication of how much the disk is going to rotate while the head is moving from one track to another. If the number of sectors/cyl change as you move across the disk, then you would need a different interleave for the outer and inner portions of the disk. Data on the outer tracks is written at a lower physical density (fewer bits per inch) and is the reason why you have the higher signal-to-noise ratio that was mentioned in another posting. -RZ p.s. If I'm wrong I'll accept that gracefully, but I don't think I am... ----------------------------------------------------------------- This list is provided by the SecurityFocus ARIS analyzer service. For more information on this free incident handling, management and tracking system please see: http://aris.securityfocus.com
This archive was generated by hypermail 2b30 : Thu Jul 12 2001 - 13:43:20 PDT